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24u^2+57u+18=0
a = 24; b = 57; c = +18;
Δ = b2-4ac
Δ = 572-4·24·18
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-39}{2*24}=\frac{-96}{48} =-2 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+39}{2*24}=\frac{-18}{48} =-3/8 $
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